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101x-72x^2=35
We move all terms to the left:
101x-72x^2-(35)=0
a = -72; b = 101; c = -35;
Δ = b2-4ac
Δ = 1012-4·(-72)·(-35)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(101)-11}{2*-72}=\frac{-112}{-144} =7/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(101)+11}{2*-72}=\frac{-90}{-144} =5/8 $
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